92
|
Great! Your answer is right.
The signal of the proton HA in |
|
is split into |
six individual lines, since HM
and HX
are not equivalent. Therefore their spin-spin couplings to HA are
independent from each other. HA
gives rise to a multiplet with
MA
= (nM
+ 1) · (nX
+ 1). |
|
Did you arrive at a different answer? Check on page 91 for additional explanations. |
Continuing from here, what would be the ratio of
the intensities of the individual lines in the HA
signal be?
Compare your answer to the solution on page
101! |
|