44
|
Answers:
| group |
d |
Dn
[Hz] at |
| |
[ppm] |
250 MHz |
400 MHz |
| CH3 |
1.1 |
275 |
440 |
| CH2 |
2.5 |
625 |
1000 |
| CH |
7.1 |
1775 |
2840 |
If your answers were right, then return to the problem on page 40.
If you made a mistake in your calculations, then have a close look at
the following example for the calculation:
| given: |
dCH3 |
= |
1.1 ppm |
| wanted: |
DnCH3
( n0=250
MHz) |
|
|
| |
dCH3 |
= |
(DnCH3
. 106) / n0
, |
| |
1.1 |
= |
(DnCH3
. 106) / (250
. 106Hz) , |
| |
DnCH3 |
= |
1.1 .
10-6 . 250 .
106Hz , |
| |
DnCH3 |
= |
275 Hz. |
Now go back to page
42 and try to redo the problem.
|
|